# Line slope calculator 2x+3y=42

**Straight line given by points A[6; 10] and B[9; 8]**

## Calculation:

**Slope-intercept form of line:**y = -0.6667x+14

**Canonical form of the line equation:**2x+3y-42 = 0

**Parametric form of the line equation:**

x = 3t+6

y = -2t+10 ; t ∈ R

**Slope:**m = -0.6667

**Slope angle of line: φ =**-33°41'24″ = -0.588 rad

**X intercept:**x

_{0}= 21

**Y intercept:**y

_{0}= q = 14

**Distance line from the origin:**d

_{0}= 11.6487

**The length of the segment AB: |AB| =**3.6056

**Vector: AB =**(3; -2)

**Normal vector: n =**(2; 3)

**Midpoint of the segment AB: M =**[7.5; 9]

**Perpendicular Bisector equation:**3x-2y-4.5 = 0

**Vector OA = (6; 10) ; |OA| = 11.6619**

**Vector OB = (9; 8) ; |OB| = 12.0416**

**Scalar product OA .OB = 134**

**Angle ∠ AOB = 17°24'10″ = 0.3037 rad**