# Line slope calculator 8x+y=10

**Straight line given by points A[0; 10] and B[1; 2]**

## Calculation:

**Slope-intercept form of line:**y = -8x+10

**Canonical form of the line equation:**8x+y-10 = 0

**Parametric form of the line equation:**

x = t

y = -8t+10 ; t ∈ R

**Slope:**m = -8

**Slope angle of line: φ =**-82°52'30″ = -1.4464 rad

**X intercept:**x

_{0}= 1.25

**Y intercept:**y

_{0}= q = 10

**Distance line from the origin:**d

_{0}= 1.2403

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(1; -8)

**Normal vector: n =**(8; 1)

**Midpoint of the segment AB: M =**[0.5; 6]

**Perpendicular Bisector equation:**x-8y+47.5 = 0

**Vector OA = (0; 10) ; |OA| = 10**

**Vector OB = (1; 2) ; |OB| = 2.2361**

**Scalar product OA .OB = 20**

**Angle ∠ AOB = 26°33'54″ = 0.4636 rad**