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Evolutionary Genetic Models of the Ovarian Time Bomb Hypothesis for the Evolution of Genomic Imprinting
Anton E. Weissteina, Marcus W. Feldmanb, and Hamish G. Spenceraa Department of Zoology, University of Otago, Dunedin 9001, New Zealand
b Department of Biological Sciences, Stanford University, Stanford, California 94305
Corresponding author: Anton E. Weisstein, University of Otago, P.O. Box 56, Dunedin 9001, New Zealand., anton.weisstein{at}stonebow.otago.ac.nz (E-mail)
Communicating editor: M. A. ASMUSSEN
| ABSTRACT |
|---|
At a small number of loci in eutherian mammals, only one of the two copies of a gene is expressed; the other is silenced. Such loci are said to be "imprinted," with some having the maternally inherited allele inactivated and others showing paternal inactivation. Several hypotheses have been proposed to explain how such a genetic system could evolve in the face of the selective advantages of diploidy. In this study, we examine the "ovarian time bomb" hypothesis, which proposes that imprinting arose through selection for reduced risk of ovarian trophoblastic disease in females. We present three evolutionary genetic models that incorporate both this selection pressure and the effect of deleterious mutations to elucidate the conditions under which imprinting could evolve. Our findings suggest that the ovarian time bomb hypothesis can explain why some growth-enhancing genes active in early embryogenesis [e.g., mouse insulin-like growth factor 2 (Igf2)] have evolved to be maternally rather than paternally inactive and why the opposite imprinting status has evolved at some growth-inhibiting loci [e.g., mouse insulin-like growth factor 2 receptor (Igf2r)].
THE unequal expression in mammals of some maternally and paternally derived genes known as genomic imprinting reduces (or even eliminates) the masking benefits of diploidy. (For a review of the benefits of diploidy over haploidy see ![]()
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A number of criticisms of this hypothesis can be made (![]()
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Nevertheless, one version of this suggestion, the ovarian time bomb hypothesis (OTBH; ![]()
In this article, we develop three evolutionary genetic models of how imprinting could evolve under the assumptions of the OTBH. These models allow us to predict when an imprintable allele can invade a population originally fixed for a nonimprintable ancestral allele, when the nonimprinting allele can invade a population fixed for imprinting, and when the two alleles can coexist. The first model describes the case of maternal inactivation; the others deal with paternal inactivation.
| MODEL FORMULATION AND ANALYSIS |
|---|
Model 1: Maternal inactivation and deleterious mutation:
This model adapts the analysis of ![]()
1). Heterozygote females would enjoy an intermediate fitness of 1 - hs; in the absence of segregation distortion, the imprintable allele should be passed to one-half of a heterozygote female's eggs, so we would expect h = 1/2. Males, of course, experience no cancer risk from expressing the growth factor in their gametes, so all of their fitnesses would be unity.
Under this simple model, the imprintable allele a always confers a selective advantage over the nonimprintable allele and should therefore become fixed in the population. This analysis, however, fails to consider the costs of haploidy, particularly the loss of masking of recessive deleterious mutants (![]()
![]()
1) because they lack a functional copy of the gene. Note that this selection pressure, unlike that imposed by ovarian cancer, applies equally to both sexes. Assuming that a* acts like a null allele, this mutant will also confer a reduced risk of cancer, since it fails to produce sufficient growth factor to initiate development when present in an unfertilized egg. We can then construct Table 1 to list the nine distinct genotypes and their relative fitnesses in both females and males.
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Let us define f1, f2, and f3 as the respective frequencies of the A, a, and a* alleles in females and m1, m2, and m3 as the corresponding frequencies in males (thus,
fi =
mi = 1). We then derive the following recursions for allele frequencies in the following generation,
![]() |
(1a) |
![]() |
(1b) |
![]() |
(1c) |
![]() |
(1d) |
![]() |
(1e) |
![]() |
(1f) |
where Tf and Tm are the mean viabilities of females and males, respectively, given by the sums of the right-hand sides of the above equations, and
![]() |
(1g) |
and
![]() |
(1h) |
This system of equations has multiple equilibria (i.e., values of f1, f2, f3, m1, m2, and m3 that satisfy Equation 1aEquation 1b HREF="#FD1c">Equation 1cEquation 1dEquation 1eEquation 1fEquation 1gEquation 1h with the primes removed from the left-hand sides). However, several of these equilibria are associated with allele frequencies that are complex, less than zero, or greater than unity. The only four biologically feasible solutions are: (i) the fixation of a* (i.e., f1 = f2 = m1 = m2 = 0, f3 = m3 = 1), which we denote equilibrium M1; (ii) a mutation-selection balance between a and a*, denoted M2 and given by
and
; (iii) a mutation-selection balance between A and a*, denoted M3 (see Appendix A for allele frequencies); and (iv) a mutation-selection balance among all three alleles, denoted M4 (see Appendix A for allele frequencies). Fig 1 plots these equilibria and the system's evolutionary trajectories for a representative set of parameter values.
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Stability analysis:
Near equilibrium M1 (fixation of a*), we linearize the system (1) and solve for the eigenvalue that governs increase of A when it is rare. This eigenvalue is less than unity, and equilibrium M1 is stable to invasion by A, if
![]() |
(2a) |
Using the same procedure, we find that equilibrium M1 is stable to invasion by a if
![]() |
(2b) |
At equilibrium M2 (a/a* polymorphism, A absent), the reduced two-allele system is stable when inequality (2b) is reversed; this condition is the same as that under which the allele frequencies at equilibrium M2 are biologically feasible (i.e., 0
f2, m2, f3, m3
1), so the reduced (a/a*) system is always stable. This same equilibrium is stable to invasion by A if
![]() |
(2c) |
For the two remaining equilibria, we explicitly assume h = 1/2 for the sake of algebraic tractability. Numerical iteration of recursions (1) indicates that equilibrium M3 (A/a* polymorphism, a absent) exists only when equilibrium M1 is unstable to invasion by A [i.e., t > [s + µ(4 - s)]/4, the reverse of 2a]. In fact, M3 is the root of the fourth-degree polynomial given by (A27) in APPENDIX A. It is a matter of algebra to see that to order µ, this polynomial is positive at f1 = 1 and, if t > [s + µ(4 - s)]/4, it is negative at f1 = 0. Hence, there is at least one mutation-selection balance equilibrium M3. For reasonable µ values, we have found no other solutions for an A/a* mutation-selection equilibrium. Further numerical investigation suggests that M3 is stable to invasion by allele a when
![]() |
(2d) |
and
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(2e) |
Note that all terms in the denominator of (2e) include a factor µ, but that some terms in the numerator do not. For typical values of µ, therefore, this inequality greatly restricts the values of s and/or t at which M3 is stable to a (e.g., if µ = 10-6, then the requirement that t
1 implies s < 2.9 x 10-3).
Inequality (2e) is also relevant for the existence of M4, the internal equilibrium, which is given by a cubic equation that factors to give the value of f1 reported in (A33) of APPENDIX A. After some algebra, the allele frequencies at this equilibrium are seen to be biologically feasible if both (2c) with h = 1/2 and (2e) hold. We have not been able to derive analytical conditions for the local stability of M4. However, the fact that its existence entails the local stability of M2 and M3 suggests that it should be unstable when it exists. Indeed, there are no values of s < 1 for which inequalities (2b), (2c), and (2e) hold simultaneously. For numerical verification of M4's instability, we set µ = 10-6, allowed both s and t to vary from 10-6 to 1 in logarithmic increments of 101/4, and at each such point (set of parameters) determined the equilibrium's stability. For all points at which equilibrium M4 was feasible, it was also unstable; for nearly all points at which the equilibrium was unfeasible, it was stable (the exceptions being several cases with t < 2µ). There were no instances when the equilibrium was simultaneously stable and biologically feasible. We also performed simulations for
50 specific combinations of s, t, and µ, in which we started the system near equilibrium M4 and then iterated Equation 1aEquation 1b HREF="#FD1c">Equation 1cEquation 1dEquation 1eEquation 1fEquation 1gEquation 1h over 104 generations. The equilibrium was unstable in all such trials. These combined findings strongly suggest that equilibrium M4 is never stable.
These results are summarized in Fig 2, which plots equilibrium stability over s-t phase space (assuming h = 1/2 and µ = 10-6). From this figure, we see that equilibrium M1 (fixation of a*) is stable only for very small values of t, at which selection against mutant alleles is too weak to counteract the pressure of recurrent irreversible mutations. Likewise, only equilibrium M3 (A/a* polymorphism) is stable for very small values of s, at which selection for A alleles to mask mutant a* alleles overcomes the opposing selection for decreased cancer risk. For these values of s and t, imprinting will neither increase when rare nor be maintained if already present. We contrast this result with the wide range of s and t values at which only equilibrium M2 is stable. In these regions, the decreased cancer risk associated with the a allele more than compensates for the inability to mask a* alleles, so imprinting should invade and be maintained.
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Fig 2 also demonstrates that, for small values of s and slightly larger values of t, equilibria M2 and M3 can be simultaneously stable. In this region of phase space, an imprintable allele will be maintained if present but cannot invade. For some sets of selection coefficients, therefore, maternal inactivation and full expression can both be stable evolutionary outcomes. (In a finite population, of course, genetic drift may enable the system to switch from one stable equilibrium to another.) This feature does not appear in verbal statements of the OTBH or in the quantitative-genetic model of ![]()
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Model 2: Paternal inactivation and deleterious mutation:
We can modify the previous model to make the inactivation of the a allele paternal. Verbal arguments based on the OTBH (![]()
![]() |
(3a) |
![]() |
(3b) |
![]() |
(3c) |
![]() |
(3d) |
![]() |
(3e) |
![]() |
(3f) |
|
where Tf and Tm are the mean viabilities of females and males, respectively, given by
![]() |
(3g) |
![]() |
(3h) |
Once again, this system appears to have four biologically feasible equilibria: (i) the fixation of a* (i.e., f1 = f2 = m1 = m2 = 0, f3 = m3 = 1), denoted P1; (ii) a mutation-selection balance between a and a*, denoted P2 (see Appendix B for allele frequencies); (iii) a mutation-selection balance between A and a*, denoted P3 (see Appendix B for allele frequencies); and (iv) a second mutation-selection balance between a and a*, denoted P4 (see Appendix B for allele frequencies).
Stability analysis:
Using the same procedure as in the maternal inactivation case, we find that equilibrium P1 (fixation of a*) is stable to invasion by A if
![]() |
(4a) |
This same equilibrium is stable to invasion by a if
![]() |
(4b) |
We have been unable to derive explicit stability criteria for the other three equilibria under this model. However, we can elucidate the internal dynamics of the model by means of the following argument. We see from Table 2 that the A and a alleles are selectively neutral when transmitted paternally. Under maternal transmission, however, this neutrality breaks down: A maternal A is favored over an a when paired with a paternal a* allele. Thus, in the only case where the A and a alleles are not interchangeable, the former has higher fitness. As a result, A should always tend to replace a whenever both alleles are present, although this process depends on the frequency of the deleterious mutant a* and may therefore take many generations. Extensive simulations using a wide range of parameter values (data not shown) bear out this conjecture.
In contrast to model 1, numerical iterations of system (3) show that the paternal inactivation model has a fairly simple outcome (Fig 3). We note that equilibrium P1 (fixation of a*) is stable over a much broader range of parameter values than is M1; even for large values of t, sufficiently high cancer risk s can lead to the fixation of the deleterious mutant. For most plausible values, however (i.e., where t is much greater than s), the only stable equilibrium is P3 (A/a* polymorphism). For h = 1/2, equilibrium P2 is always unstable and equilibrium P4 requires biologically unfeasible allele frequencies; consequently, the a allele is always lost. According to this model, therefore, growth-enhancing genes should not evolve paternal inactivation.
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We can also use model 2 to analyze the behavior of growth-inhibiting genes. At such a locus, the unimprintable allele A would now enjoy the selective advantage because it reduces both the chance of an egg spontaneously developing and the probability of expressing a deleterious mutant allele. We can therefore describe this system by simply requiring that s < 0 (rather than s > 0 as at growth-promoting loci). Modifying Table 1 and Table 2 appropriately, we see that the A allele now has higher fitness than the a allele under both the maternal and the paternal inactivation models, so the imprintable allele should always be selectively eliminated. Therefore, our simple model of the OTBH leaves us with no adaptive explanation for observed instances of paternal inactivation (e.g., ![]()
Model 3: Paternal inactivation, deleterious mutation, and stabilizing selection:
Alternative formulations of the OTBH, more complex than the model described above, have incorporated possible mechanisms for the evolution of paternal inactivation. The "innocent bystander" hypothesis suggests that paternal inactivation results from imprinting machinery aimed at specific physical features of trophoblast-specific genes but also present in some other genes, both paternal and maternal (![]()
![]()
, which is underexpressed when inherited paternally and overexpressed when inherited maternally. Each a
allele present in a female therefore inhibits spontaneous development in one-half of her unfertilized eggs, increasing her fitness by an amount r/2; each unimprintable A allele she carries likewise decreases the risk of such development in one-half of her eggs, decreasing her fitness by an amount s/2. (We assume here that h = 1/2; given that this is a growth-inhibiting locus, we also expect r > 0 > s.) Using Table 3, where the first allele written again represents the maternally derived allele, we can derive the following iterations,
![]() |
(5a) |
![]() |
(5b) |
![]() |
(5c) |
![]() |
(5d) |
![]() |
(5e) |
![]() |
(5f) |
|
where Tf and Tm are the mean viabilities of females and males, respectively, given by
![]() |
(5g) |
![]() |
(5h) |
This system has three biologically feasible equilibria: (i) the fixation of a* (i.e., f1 = f2 = m1 = m2 = 0, f3 = m3 = 1), denoted S1; (ii) a mutation-selection balance between a
and a*, denoted S2 (see Appendix C for allele frequencies); and (iii) a mutation-selection balance between A and a*, denoted S3 (allele frequencies same as P3; see Appendix C).
Stability analysis:
Again using the same procedure as in the maternal inactivation case, we find that equilibrium S1 (fixation of a*) is stable to invasion by A if
![]() |
(6a) |
[Note that this criterion is identical to (4a), the criterion for which equilibrium P1 is stable to invasion by A, if h = 1/2.] Equilibrium S1 is stable to invasion by a
if
![]() |
(6b) |
Turning to equilibrium S2 (a
/a* polymorphism), we find that this equilibrium is feasible precisely when inequality (6b) is violated. Within the reduced system involving only the a
and a* alleles, S1 and S2 are the only two equilibria, so S2 must be stable when S1 is unstable and vice versa. We tested this result by setting µ = 10-6, allowing r to vary from 10-7 to 1 in logarithmic increments of 101/4; at each such point, we calculated the critical value of t given by (6b) and also determined via simulation the value of t at which S2 became unstable. In all cases, the two values were equal, confirming that S2 is internally stable whenever it is feasible. For equilibrium S3, an analogous set of simulations (varying s from -1 to -10-7) demonstrated that this equilibrium is both feasible and internally stable precisely when inequality (6a) is violated, i.e., when S1 is unstable to invasion by A.
Now, when both S2 and S3 are feasible, one must be stable and the other unstable (since S1 is unstable and no other equilibria exist). We performed 40 simulations using random parameter values -1 < s < 0 < r, t < 1; in each case, S2 was stable when r + s > 0 and unstable when r + s < 0. We tested this pattern by performing 20 additional simulations with r = -s + 0.01 and 20 with r = -s - 0.01: The former group of simulations all converged to equilibrium S2 and the latter to S3. We conclude that S2 is stable and S3 unstable for r + s > 0 and that the reverse holds true for r + s < 0. (When r + s = 0, the "overexpression" of maternally inherited a
alleles is equal to the normal expression of A alleles; this case is therefore equivalent to paternal inactivation without stabilizing selection, which we have already examined under model 2.)
It is instructive to compare the feasibility of equilibria in models 2 and 3 (Fig 3 and Fig 4, respectively). Because model 3 includes a parameter r not present in model 2, the former plot has one more dimension than the latter. Moreover, this extra parameter effectively decouples the system's equilibria: The feasibility of S2 depends on r but not on s, and the feasibility of S3 depends on s but not on r, whereas the feasibilities of P2 and P3 from model 2 both depend on s. As a result of this decoupling, equilibrium S2 (mutation-selection balance of the imprintable allele under stabilizing selection) is stable over a wide range of parameter space, although P2 (the corresponding equilibrium without stabilizing selection), as we observed, is never stable. This analysis therefore elucidates the range of parameter values for which IWASA's (1998) modified version of the OTBH holds.
|
| DISCUSSION |
|---|
The results of our models validate the most basic prediction of the ovarian time bomb hypothesisthat the risk of ovarian cancer in females can lead to the evolution of maternal inactivation. The feasibility of such an evolutionary event will obviously depend on the parameter values present in a particular system. Specifically, imprinting of growth-enhancing genes can evolve most easily when the cancer risk, s, exceeds a specific threshold, calculated from (2e). Once imprinting has evolved, however, it can be maintained even if s decreases significantly below that threshold. Moreover, our results imply that polymorphism in imprinting status will not evolve under the selection regime envisaged by the OTBH, a finding in contrast to that of a similar model for the genetic-conflict hypothesis (![]()
The models also suggest possible answers to some objections that have been raised against the OTBH. One such objection states that mammalian ovarian teratomas are too rare to apply the selective pressure needed to fix an imprintable allele (![]()
4 x 10-6). We therefore conclude that the OTBH can explain the maintenance of imprinting even when the risk of ovarian cancer is very low, although that risk must be higher for imprinting to evolve in the first place.
A second objection that has been raised to the OTBH suggests that a single maternally imprinted growth-factor locus would avert the risk of ovarian trophoblast disease and that the existence of multiple such alleles represents evidence against the hypothesis (![]()
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A third objection notes that while the original version of the ovarian time bomb hypothesis might elucidate a mechanism for maternal imprinting, it cannot explain the inactivation of paternal alleles (![]()
![]()
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The OTBH has also been criticized for its inability to explain imprinting in organisms other than mammals, for example, in insects and plants (![]()
![]()
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Using evolutionary-genetic models to evaluate verbal hypotheses for the evolution of imprinting has been controversial. ![]()
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The second of HAIG's (1999) criticisms concerned ![]()
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These disagreements are important in determining the novelty of our findings. For example, the evolutionary-genetic models developed here and in ![]()
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Our models also suggest a second distinguishing prediction between the OTBH and the genetic-conflict hypothesis: The simultaneous stability of imprinting and nonimprinting for biologically plausible parameter values occurs only under the OTBH. The possibility of such a bistable system has been previously noted in a quantitative-genetic study of the genetic-conflict hypothesis (![]()
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| ACKNOWLEDGMENTS |
|---|
Financial support for this work was provided by the Marsden Fund of the Royal Society of New Zealand contract UOO916 (A.E.W. and H.G.S.) and the U.S. National Institutes of Health grants GM 28016 and GM 28428 (M.W.F.).
Manuscript received February 26, 2002; Accepted for publication May 28, 2002.
| APPENDIX A |
|---|
MATERNAL INACTIVATION
To derive equilibrium allele frequencies under model 1 (maternal inactivation), we plugged (1g) and (1h) into (1a1d), substituted f3 = 1 - f1 - f2 and m3 = 1 - m1 - m2, and set
,
,
, and
to obtain
![]() |
(A1) |
![]() |
(A2) |
![]() |
(A3) |
![]() |
(A4) |
Solving (A2) for m2, we find
![]() |
(A5) |
or
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(A6) |
or
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(A7) |
We now examine each of these cases in turn.
Case IA:
Plugging (A5) into (A1), we find that
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(A8) |
This is an unfeasible value for s; therefore, this case yields no feasible equilibria.
Case IB:
Plugging (A6) into (A1) and (A2), we find
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(A9) |
or
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(A10) |
Subcase IB1 corresponds to equilibrium M1 (fixation of a*), and Subcase IB2, to equilibrium M2 (a/a* polymorphism).
Case IC:
Plugging (A7) into (A4), we find that
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(A11) |
or
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(A12) |
But t < 1 and 0
1 - m1 - m2
1, so (A11) is clearly unfeasible. We turn instead to (A12), substituting both this equation and (A7) into (A1) to obtain Subcase IC1:
![]() |
(A13) |
or Subcase IC2:
![]() |
(A14) |
(Numerical analysis revealed that the other root of Equation A14 is negative and hence unfeasible.)
Subcase IC1:
The first condition presented in (A13) can be written as
![]() |
(A15) |
or
|
(A16) |
Note that the left-hand side of (A15) is positive, while the right-hand side is negative. This solution is therefore unfeasible. We then break (A16) down into two further subcases: h < 1/2 (Subcase IC1a) and h > 1/2 (Subcase IC1b). [If h = 1/2, then (A13) simplifies to (A15), which we have already considered.]
Subcase IC1a (h < 1/2):
The discriminant of (A16) can be rewritten as
![]() |
(A17) |
For h < 1/2, this value will be negative, so the roots of (A16) will be complex and hence unfeasible. Therefore, this subcase has no feasible solutions.
Subcase IC1b (h > 1/2):
Define Q = 2s(1 - µ - 2h + µh), c = 8s(1 - µ)(1 - hs)(2h - 1), d = 4s(2h - 1), e = 8µs2(1 - h)(2h - 1), and f = 4µ2s2(1 - h)2. Then c, d, e, f > 0 > Q, so we can write the minus root of (A16) as
![]() |
(A18) |
which is clearly unfeasible. Similarly, we can write the plus root of (A16) as
![]() |
(A19) |
which is also unfeasible. Therefore, this subcase also has no feasible solutions, concluding our analysis of Subcase IC1.
Subcase IC2:
We can plug (A7) and (A12) into (A3) to obtain
![]() |
(A20) |
or Subcase IC2b:
![]() |
(A21) |
or Subcase IC2c:
![]() |
(A22) |
Subcase IC2a:
Combining Equation A14 and Equation A20, we find that
![]() |
(A23) |
or
![]() |
(A24) |
Note that (A23) is just the first condition presented in (A13), which has already been analyzed in Subcase IC1. Turning to (A24), we solve for f1, then substitute this result into (A20) to solve for m1, and finally plug these results into (A7) to solve for m2, obtaining
![]() |
(A25) |
By inspection, m2 < 0, so this subcase has no feasible solutions.
Subcase IC2b:
Substituting (A14) into (A21) and solving for f1, we find that
, where
![]() |
(A26) |
If we assume h = 1/2 and discard quadratic and higher-order terms in µ, we obtain
![]() |
(A27) |
Numerical analysis reveals that at most one root of this equation is biologically feasible over the range 0 < s, t < 1, giving a unique solution for f1. Theoretically, we can then calculate other allele frequencies by substituting this value successively into (A14), (A7), and (A20), but this is algebraically cumbersome. An easier approach is to repeat the above analysis under the assumption f2 = m2 = 0; this procedure gives precisely the same coefficients given in (A26). Both approaches will yield the same solution for f1 and hence for m1, m2, and f2. Since f2 = m2 = 0 under the second approach, these allele frequencies must be zero under the original derivation as well. Substituting this result into (A7) yields
![]() |
(A28) |
(The other root is negative and hence unfeasible.) These allele frequencies define equilibrium M3 (A/a* polymorphism). As an alternative derivation, given that f2 = m2 = 0, we can solve (A2) for f1 and then (A1) for m1, obtaining
![]() |
(A29) |
and
![]() |
(A30) |
where
![]() |
(A31) |
This alternative formulation is used to compare model 1 (maternal inactivation) to model 2 (paternal inactivation).
Subcase IC2c:
Substituting (A14) into (A22) and solving for f1, we find that
, where
![]() |
(A32) |
If we assume h = 1/2, then a'' = 0, so the equation becomes quadratic with the following solutions:
![]() |
(A33) |
or
![]() |
(A34) |
Clearly, (A33) yields f1 > 1, so (A34) is the only feasible root. We can then calculate the other allele frequencies by substituting this value successively into (A14), (A7), and (A12): These frequencies define equilibrium M4 (three-allele polymorphism). We have now examined all subcases, so there are no further equilibria under maternal inactivation.
| APPENDIX B |
|---|
PATERNAL INACTIVATION
To derive equilibrium allele frequencies under model 2 (paternal inactivation without stabilizing selection), we plugged (3g) and (3h) into (3a3d), substituted f3 = 1 - f1 - f2 and m3 = 1 - m1 - m2, and set
, and
to obtain
![]() |
(B1) |
![]() |
(B2) |
![]() |
(B3) |
![]() |
(B4) |
Solving (B2) for f2, we find
![]() |
(B5) |
or
![]() |
(B6) |
or
![]() |
(B7) |
Clearly, (B5) implies that f1 > 1; therefore, case IIA yields no feasible equilibria.
Case IIB:
Plugging (B6) into (B4) and solving for m2, we obtain
![]() |
(B8) |
Substituting both this value and (B6) into (B3) yields
![]() |
(B9) |
or
![]() |
(B10) |
where
![]() |
(B11) |
Subcase IIB1 corresponds to equilibrium P1 (fixation of a*), while the minus and plus roots of subcase IIB2 correspond to equilibria P2 and P4 (a/a* mutation-selection balance under paternal inactivation), respectively. Numerical analysis demonstrates that P4 is feasible only if h > 1/2; when both P2 and P4 are feasible, f2 is greater at the former than at the latter.
Case IIC:
Solving (B4) for m2, we find that
![]() |
(B12) |
or
![]() |
(B13) |
Subcase IIC1:
Solving (B12) for m1, we obtain
![]() |
(B14) |
For this solution to be feasible, we must have both m1 > 0 and m1 < 1. The former condition requires that the denominator of (B12) is negative, so the latter condition can be expressed as
![]() |
(B15) |
But as we saw in examining (B5), the right-hand side of this inequality is greater than one. Therefore, this subcase leads to no feasible solutions.
Subcase IIC2:
Substituting both (B7) and (B13) into (B3), we obtain Subcase IIC2a:
![]() |
(B16) |
or
![]() |
(B17) |
or
![]() |
(B18) |
where
![]() |
(B19) |
Subcase IIC2a:
Combining the two conditions of (B16), we find that
![]() |
(B20) |
which is clearly greater than one and hence unfeasible.
Subcase IIC2b:
Substituting (B7), (B13), and (B17) into (B1), we obtain
![]() |
(B21) |
or
![]() |
(B22) |
where
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(B23) |
By numerical analysis, at most one root of this equation is biologically feasible over the range 0 < s, t < 1, producing a unique solution for m1 that corresponds to equilibrium P3 (A/a* polymorphism). As under the maternal case, the easiest way to calculate the other allele frequencies is to repeat the above analysis under the assumption f2 = m2 = 0; this procedure gives the same coefficients as (B23). Both approaches will therefore yield the same solution for m1 and hence for f1, m2, and f2, implying that f2 = m2 = 0. Moreover, we note that equations (B17), (B22), and (B23) are, respectively, identical to (A29), (A30), and (A31) from the maternal inactivation model. Therefore, allele frequencies at equilibrium P3 are identical to those at equilibrium M3.
Subcase IIC2c:
For the purposes of algebraic tractability, we hereafter assume that h = 1/2. We then separately examine the cases a = b = 0 (Subcase IIC2ci), a = 0
b (Subcase IIC2cii), and a
0 (Subcase IIC2ciii).
Subcase IIC2ci (a = b = 0):
Substituting h = 1/2 into (B19), setting b = 0, and solving for m1, we find that
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(B24) |
We have already examined the first two solutions; by inspection, the third solution is negative and hence unfeasible.
Subcase IIC2cii (a = 0
b):
Substituting h = 1/2 into (B19), setting a = 0, and solving for m1, we derive
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(B25) |
We can then solve (B18) and (B19) for f1 and plug in (B25) to obtain
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(B26) |
Substituting (B7), (B13), (B25), and (B26) into (B1), we find that
![]() |
(B27) |
or
![]() |
(B28) |
or Subcase IIC2cii.b:
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(B29) |
Equation B27 implies that s = 4/(3 - µ); this value is greater than one and hence unfeasible.
Subcase IIC2cii.a:
Substituting back into (B25) and (B26), we obtain f1 = m1 = 0. This case has already been analyzed (Case IIB) and can therefore be excluded from further consideration.
Subcase IIC2cii.b:
Solving Equation B29 for t, we obtain
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(B30) |
Feasibility requires t < 1, which implies
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(B31) |
This value of s is greater than one and hence unfeasible. This concludes our analysis of subcase IIC2cii.
Subcase IIC2ciii (a
0):
From (B18),
![]() |
(B32) |
where the coefficients a, b, c are given by (B19). We set h = 1/2, substitute (B7), (B13), and (B32) into (B1), and solve for m1 to obtain
![]() |
(B33) |
or
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(B34) |
or Subcase IIC2ciii.b:
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(B35) |
As we saw in examining Equation B27, (B33) is unfeasible, so we can turn to the other two possibilities.
Subcase IIC2ciii.a:
Substituting (B34) into (B19), we find that a = 0. But this contradicts our assumption for Subcase IIC2ciii. Therefore, this subcase can be excluded.
Subcase IIC2ciii.b:
Solving (B35) for m1, we find



































































































