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The Correlation Between Relatives on the Supposition of Genomic Imprinting
Hamish G. Spenceraa Department of Zoology, University of Otago, Dunedin, New Zealand
Corresponding author: Hamish G. Spencer, University of Otago, P.O. Box 56, Dunedin, New Zealand., h.spencer{at}otago.ac.nz (E-mail)
Communicating editor: T. F. C. MACKAY
| ABSTRACT |
|---|
Standard genetic analyses assume that reciprocal heterozygotes are, on average, phenotypically identical. If a locus is subject to genomic imprinting, however, this assumption does not hold. We incorporate imprinting into the standard quantitative-genetic model for two alleles at a single locus, deriving expressions for the additive and dominance components of genetic variance, as well as measures of resemblance among relatives. We show that, in contrast to the case with Mendelian expression, the additive and dominance deviations are correlated. In principle, this correlation allows imprinting to be detected solely on the basis of different measures of familial resemblances, but in practice, the standard error of the estimate is likely to be too large for a test to have much statistical power. The effects of genomic imprinting will need to be incorporated into quantitative-genetic models of many traits, for example, those concerned with mammalian birthweight.
THE expression of a gene at a genomically imprinted locus depends on the parent from which it was inherited. For example, in most fetal tissues of all eutherian and marsupial species examined to date, the maternal copy of the insulin-like growth factor II (Igf-2) gene is inactive, only the paternal copy being transcribed (![]()
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Under standard Mendelian expression, the number of phenotypic classes at a locus with k alleles is k(k + 1)/2. Complete inactivation of one allele would reduce the number of phenotypic classes to k. The more general view of imprinting outlined above, however, means that reciprocal heterozygotes need not have the same average phenotype. Consequently, the number of phenotypic classes is k2, greater than under Mendelian expression. This increase has a number of implications for standard population-genetic processes and phenomena. For instance, because it discriminates among different phenotypic classes, natural selection acts differently (![]()
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This article thus adds to the literature on the effect of sex differences on quantitative characters, previous work considering models of sex-linked inheritance (![]()
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| MODEL |
|---|
We consider a locus subject to imprinting, which has two alleles, A1 and A2. By denoting a genotype AiAj, we mean that the Ai allele is maternally derived and the Aj allele is paternally derived. Imprinting means that reciprocal heterozygotes may differ in their average phenotypes. In the case of complete inactivation of the maternally derived gene, for instance, the average A1A2 phenotype is the same as that of the A2A2 homozygotes, whereas the average A2A1 phenotype is the same as that of A1A1 homozygotes. Since most cases of imprinting show some degree of biallelic expression in some tissues at some stage of development, however, we do not assume that heterozygotes are phenotypically equivalent to one or another homozygote.
Genetic components of variance:
Following standard genetic models (see, e.g., ![]()
![]()
![]()
d1, d2
a, since partial inactivation of a gene is unlikely to produce a more extreme phenotype than that of the homozygote for the unimprinted copy. Nevertheless, we do not make this assumption in most of what follows.
|
The mean genotypic value over the whole population is given by
![]() |
(1) |
When
we recover the standard Mendelian value of a(p - q) + 2dpq (![]()
![]() |
(2) |
Values for the three other genotypes are found similarly and are shown in Table 1.
|
We can now calculate the breeding values for each of the four genotypic classes. A breeding value is defined to be twice the difference between the mean genotypic value of that class's offspring and the population mean (![]()
![]() |
(3) |
in which
. Similarly, the breeding value for A1A1 females is given by
![]() |
(4) |
in which
. When d1 = d2 we have
, say, and we recover the standard Mendelian breeding value for A1A1 homozygotes of 2q
(![]()
|
The dominance deviation for a genotypic class is defined as the difference between the genotypic deviation and the breeding value. Since the latter differs for males and females, so too does the dominance deviation. A little algebra gives the values shown in Table 1; again their mean is zero and when d1 = d2, the sex difference disappears, and we recover the standard Mendelian values. Note also that, as is the case without imprinting, these values are independent of a and are zero when d1 = d2 = 0.
The overall genetic variance of the population is the variance of the genotypic deviations:
![]() |
(5) |
When d1 = d2 = d, this equation reduces to
, the standard value.
The additive genetic variances for males and females are given by the respective variances of their breeding values,
![]() |
(6) |
and, similarly,
![]() |
(7) |
The dominance genetic variance for each sex is, by definition, the variance of dominance deviations. For males, this variance is given by
![]() |
(8) |
and for females it is
![]() |
(9) |
say. Even though the dominance deviations are different for males and females, their variances are the same. Again, as expected,
2D is independent of a, and when d1 = d2 = d reduces to the Mendelian (2pqd)2, which is zero when d = 0. Note, however, that
2D
0 when the average of the heterozygote genotypic values [i.e., 1/2(d1 + d2)] is zero (unless d1 = d2 = 0).
With Mendelian expression the breeding values and dominance deviations are uncorrelated, but this result does not hold under imprinting. The covariance for males is given by
![]() |
(10) |
whereas that for females is similarly shown to be
![]() |
(11) |
We can immediately see that both these covariances are zero in the absence of imprinting. Moreover, since the sum of each genotype's breeding value and dominance deviation is its genotypic deviation
, we should have
![]() |
(12) |
which is easily verified.
The male and female correlations between breeding values and dominance deviations are therefore given by, respectively,
![]() |
(13) |
and
![]() |
(14) |
A graph of
ADm as a function of d2, with other parameter values fixed, is shown in Fig 3. Note that when imprinting causes heterozygotes to be more like homozygotes for the maternally derived allele (i.e., complete or partial paternal inactivation, d2 < d1), then
ADf is negative: female additive and dominance deviations are negatively correlated.
|
Resemblance between relatives:
We can now calculate various correlations between relatives in terms of the above components of variance, comparing the expressions with the standard, Mendelian formulas. Take, for instance, the covariance between the genotypic values of fathers and their offspring assuming random mating,
OPm. We follow the treatment of ![]()
2Am +
ADm). This result can also be derived from first principles, with the help of Table 2 and Table 3, as follows:
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(15) |
|
|
Hence, the regression coefficient of mean offspring phenotypes plotted against that of their fathers is given by
, in which
is the (total) phenotypic variance of the population and
2E is the so-called environmental variance. In deriving this formula, we assume
2P to be the same for males and females; if it is not, then the regression must be calculated for sons and daughters separately and the latter multiplied by the ratio of the square root of the total variance,
P, in males to that in females (![]()
Similarly, the covariance between maternal and offspring genotypic values is given by
![]() |
(16) |
and the regression of offspring against mothers is
. Graphs of ßOPm and ßOPf as functions of d2 for two different values of d1 are shown in Fig 4. Also shown is the standard parent-offspring regression coefficient (i.e., assuming no imprinting), ßOP, which is not the mean of the two imprinting values.
|
Interpreting differences between ßOPm and ßOPf is problematic, however, since if the latter is larger it may be due to a maternal effect rather than imprinting. This problem can be alleviated somewhat if the correlation among half-sibs is also calculated. The covariance of half-sibs can be found by the same logic as above. Remembering that the covariance among offspring who share a mother but not a father is the variance of the genotypic means of those half-sib groups and that these means are one-half the breeding values of the mothers, we have that the covariance is one-quarter the mothers' additive variance:
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(17) |
Hence, the correlation among half-sibs who share a mother is
. Similarly, the covariance among half-sibs who share a father is
and the correlation is
.
This latter value should be unaffected by maternal effects provided mating has been at random (![]()
ADm:
![]() |
(18) |
If this value (or equivalently, the simpler ßOPm - 2
HSPm) is not zero, there is evidence of imprinting. Hence, in principle, we can use the standard estimates of regression (bOPm) and correlation (rHSPm) to obtain a test statistic that is nonzero when imprinting occurs:
![]() |
(19) |
Moreover, provided -a
d1, d2
a, the sign of c is the same as that of d1 - d2.
The significance of the value of c obtained from an experiment can be deduced by considering the sampling distributions of bOPm and rHSPm. For instance, if n offspring from each of N families are used in assessing the regression of offspring means on their fathers and
is the correlation among offspring within families, the variance of bOPm is approximately
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(20) |
(![]()
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(21) |
Hence, the variance of c is, approximately,
![]() |
(22) |
in which
br is the covariance between bOPm and rHSPm. An approximate test for significance (i.e., testing the null hypothesis that the true value for c is zero) is thus given by seeing if the interval c ± 2
c includes zero or not.
Unfortunately, although simulations show that values of c are very close to normally distributed, this test probably lacks sufficient power to be useful in many situations. For example, under the null hypothesis of no imprinting (d1 = d2 = d), the smallest standard errors arose when there was no environmental variance (i.e.,
) and when the two alleles were equally frequent (p = q = 0.5). When d was in the range 0.00.25, the variances of c values estimated from 100 fathers and two half-sib offspring were
0.03, which correspond to confidence intervals for
ADm of ±0.35, approximately. For
ADm to be significant, we would require the genotypic means of the reciprocal heterozygotes to be quite different: d1 = -0.5 and d2 = 0.5 (and hence
), for instance. If the environmental variance was not negligible
, for examplethen the confidence interval increased to the extent that no c values were able to be significant for this size data set.
| DISCUSSION |
|---|
At a genomically imprinted locus, the maternal and paternal copies are differentially expressed. Hence, the mean phenotypes of reciprocal heterozygotes, identical under the rules of standard Mendelian expression, need no longer be the same. We show that this loss of symmetry destroys much of the simplicity that occurs in the standard single-locus models of quantitative genetics and their well-known measures of genetic variance and resemblances among relatives. Under imprinting, breeding values and additive genetic variances are different for males and females. Although male and female dominance deviations are also different, dominance genetic variances for males and females are identical. Breeding values and dominance deviations are no longer uncorrelated, which means that the genetic variance cannot be partitioned into the usual additive and dominance variances.
Under imprinting, offspring will more closely resemble the parent that does not downregulate expression in the genes it transmits. In the case of Igf-2, for instance, the maternal copy is silenced in a large number of fetal tissues and so offspring phenotypes resulting from Igf-2 expression should be more similar to those of fathers than those of mothers. ![]()
, for example, the regression of offspring against their fathers is
![]() |
(23) |
whereas, assuming no maternal effects, the regression of offspring against their mothers is
![]() |
(24) |
We can contrast these values with various hypothetical nonimprinting examples, again assuming a = 1, two equally frequent alleles
, and an environmental variance,
2E, of 1, but enforcing
. When d = 0,
![]() |
(25) |
whereas d = 0.8 gives ßOP = 0.379. The former (d = 0) example shows that the effect of imprinting that has the same mean genotypic value for heterozygotes is to increase the regression of offspring against the parental sex that does not downregulate the genes it passes on. The latter (d = 0.8) example shows, however, that if one sex begins to downregulate those genes, both regressions will decrease.
The derivations above do not apply to X-linked genes, of course. Ironically, however, the situation for sex-linked loci has been the subject of previous work. In marsupials (and eutherian placentas), dosage compensation is effected by condensation of the paternally derived X chromosome (![]()
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and
), for instance,
pq (although
). In sex-linked models, however, these covariances are always zero.
In principle, the nonzero correlation between breeding values and dominance deviations under imprinting may be used to test if imprinted loci are influencing a trait of interest. Continuing our numerical example above, the correlation among half-sibs sharing a father is
![]() |
(26) |
and we can recover the value of
ADm (-0.72) from Equation 18:
![]() |
(27) |
Unfortunately, the large standard error of this estimate of
ADm limits its use as a practical statistical test for the presence of imprinting. Only in cases with large data sets and large differences in the genotypic values of the reciprocal heterozygotes will a 95% confidence interval exclude zero, the value under the null hypothesis of standard expression. Again using the illustrative numbers above, 1000 simulations showed that, when obtaining both the regression and correlation estimates from families of two half-sibs of 100 fathers, 95% of the estimates of
ADm fell in the range from -2.136 to 0.625. Using 500 families sufficiently reduced this interval to (-1.378, -0.156).
Of course, the model developed above is extremely simple in many ways. Most importantly, (i) it is concerned with a single locus only and so can ignore the complicating effects of epistasis; (ii) it assumes that there is no genotype by environment (G x E) interaction; and (iii) it avoids dealing with maternal effects. All of these aspects limit the direct applicability of the model. [The extension to several additive loci is presumably straightforward, however; see ![]()
and
.] The importance of these limitations becomes apparent when we recall that many imprinted loci have effects on fetal growth (![]()
| ACKNOWLEDGMENTS |
|---|
I thank A. G. Clark, K. G. Dodds, R. C. Lewontin, A. E. Weisstein, and two anonymous referees for helpful comments on the manuscript. This work was supported by the Marsden Fund of the Royal Society of New Zealand (contract UOO916).
Manuscript received September 11, 2001; Accepted for publication February 18, 2002.
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. These values give µ = 19a/32, 










(solid line), and
(dotted line). Note that for negative d1, 















